Number of binary search tree having n vertices
(2n)!/(n!*(n+1)!)
which is equals to the nth CATALAN number
CATALAN series
1, 1, 2, 5, 14, 42, 132, 429, 1430, 4862, 16796, 58786, 208012, 742900, 2674440, 9694845, 35357670, 129644790,477638700, 1767263190, 6564120420, 24466267020, 91482563640, 343059613650, 1289904147324, 4861946401452..........
Recurrence relation for catalan series..
c(0)=1;
c(n+1)=sigma(c(i)*c(n-i)) over i=0 to n.
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